Keliling dan Luas Trapesium berturut-turut adalah...cm,... cm^2
228, 64
058, 247
247, 58
64, 228
228, 64
058, 247
247, 58
64, 228
Jawab:
segitiga BCF:
BF = (24 - 14)/2 = 10/2 = 5 cm
CF = 12 cm
BC = [tex]\sqrt{BF^{2}+ CF^{2} }[/tex]
= [tex]\sqrt{5^{2}+ 12^{2} }[/tex]
= [tex]\sqrt{169}[/tex]
= 13 cm
Keliling trapesium = jumlah sisi sejajar + 2(sisi miring)
= DC + AB + 2×BC
= 14 + 24 + 2×13
= 38 + 26
= 64 cm
Luas trapesium = 1/2 × jumlah sisi sejajar x× tinggi
= 1/2 × (24 + 14) × 12
= 6×38
= 228 cm²
[answer.2.content]
